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How Child Types Borrow and Extend Behavior from Parent Types
Data Structures and Algorithms · Chapter 3: Thinking in ObjectsSection 3.3 · lesson 9 of 8714 min · free with a free account
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In this lesson
Reuse and extend parent behavior with inheritance, overriding and polymorphism.
- Create a child class with extends and chain constructors with super
- Override methods with the Override annotation and distinguish overriding from overloading
- Explain declared versus actual types and how dynamic dispatch picks a method
- Use upcasts, downcasts, instanceof and protected access safely
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Transcript
Everything said in the video, section by section (1,934 words). Read along, or search it.
Opening Question
Payroll Without Writing Things Three Times
Imagine a payroll program. Every employee has a name and a base salary, and can be asked for a pay amount. Managers also get a bonus. Engineers also get an on-call allowance. Without help, you'd write the name, the salary and the pay logic three times, and every later fix would have to be made in three places. So how do you write the shared part once, and let each special case add only what makes it special?
Key Idea
Is-a Versus Has-a
Writing the shared part once, and letting each child type add what's different, is called inheritance. The test for whether it fits is a sentence: a manager is an employee. If that sounds natural, the child can stand in anywhere its parent is expected. If it sounds odd, a car is an engine, the relationship is really has-a, and the car should simply hold an engine inside it. In Java, a type extends exactly one parent. And a type that names no parent quietly gets one anyway: Object, the type at the top of every chain.
Parent Class
The Employee Parent Class
Here's the parent, Employee, with private fields, a constructor, and three methods: get name, pay, and describe. Describe builds a sentence from the name, and from whatever pay returns. Remember that, because it matters later.
Child Class
Manager Extends Employee
And here's the child. Manager extends Employee. The keyword extends is the whole mechanism. What the child declares itself, the bonus field and get bonus, is added on top of everything it inherits.
Demo
Inherited Methods That Just Work
This program makes a manager, then asks for its name, its description, and its bonus. Run it: Asha, Asha earns five thousand point zero, and eight hundred point zero. Manager wrote no get name and no describe, yet both work. They were inherited.
What Is Inherited
Private Fields and Missing Constructors
A child carries every accessible member of its parent. Public and protected methods work with no extra code. One surprise: a manager object really does contain the parent's private base salary, because pay can't be computed without it. But the child's own code isn't allowed to name that field. And constructors are never inherited at all.
Constructor Chain
Calling Super First
Because constructors aren't inherited, a child constructor needs a way to set up the parent part of the object. That's super, with parentheses. It calls a constructor of the parent, and it must be the first statement. If you write no super call, Java inserts one for you, super with no arguments. The result is a chain: every constructor calls its parent's first, all the way up to Object. Here's a three-level chain. Only Boss calls super itself, and Worker's constructor has no super line at all. Run it: Person, then Worker, then Boss. The parent part is always built first.
Common Error
No Matching Parent Constructor
That rule has a consequence. Employee's only constructor needs a name and a salary. So when a child's constructor has no super call, the automatic super with no arguments has nothing to call. Constructor Employee cannot be applied to given types. Required: string, double. Found: no arguments. The fix is to take those two values, and pass them up with super, as the first line. A constructor may instead begin with this, which hands the work to another constructor of the same type. It can use this or super, never both.
Overriding
A Manager's Pay Includes the Bonus
Inheriting a method doesn't force you to keep its behavior. A child may supply its own version, with the same name and the same parameter list. That's overriding. A manager's pay should include the bonus, so Manager overrides pay. Super dot pay calls the parent's version, so the child extends the behavior instead of rewriting it. Run a short program: five thousand eight hundred. And describe, written in Employee, prints five thousand eight hundred too. Inside an inherited method, a call to pay still reaches the child's override.
Annotation
Override Catches a Misspelled Name
The at override line is a promise to the compiler: this method replaces one from a parent. It changes nothing at run time, but it turns silent mistakes into errors. Here the name is mistyped, with a capital P. Method does not override or implement a method from a supertype. Without the annotation, capital P pay would compile happily as a brand-new method, and pay would quietly keep its old behavior. So write at override on every override.
Override Rules
Four Rules for a Valid Override
A valid override follows four rules. Same name and parameter types: pay with an int parameter is a different method. The return type is the same, or a more specific child type. Access is the same or wider, never narrower. A package-level close method can't replace a public one, and the compiler says it's attempting to assign weaker access privileges. And private, static and final methods can't be overridden: private ones are invisible to the child, static ones are hidden, not overridden, and final ones are locked.
Comparison
Overloading Versus Overriding
Overriding and overloading sound alike, but they solve different problems. Overloading means several methods share a name, with different parameter lists. And the choice is made at different moments. An overloaded call is settled by the compiler, before the program runs, using only the declared types of the arguments. Both variables here point to a manager. But e is declared as Employee, so the compiler picks show, Employee. M picks show, Manager. And the very same object still answers e dot pay with the manager's five thousand eight hundred, because overriding is decided later, at run time.
Key Rule
Compiler Picks Overloads, Runtime Picks Overrides
Keep the two stages apart, and many puzzles disappear. Overloads differ in their parameters, and the compiler picks one from declared types. Overrides have identical parameters, and the running program picks one from the actual object. Only overrides are checked by at override.
Common Trap
An Equals That Overloads by Mistake
A famous trap: overloading when you meant to override. The equals method inherited from Object takes an Object. Writing equals that takes a Box doesn't override it. It adds a second method beside it. These two calls compare the same pair of boxes, yet the answers differ: true, then false. With the argument declared as Box, the new overload is chosen. Declared as Object, only the inherited identity check applies. Anything in Java that calls equals without knowing about boxes uses the inherited version. Adding at override would have stopped this program from compiling, and exposed the mistake at once.
Quick Check
Greet With an Object Holding Text
Quick check. Two greet methods: one takes an Object, one takes a String. X is declared as Object, but holds the text hi. What does the program print? Pause, and predict. It prints, object string. Overloads are chosen by the compiler, from declared types. X is declared Object, so greet of x calls the Object version, even though it holds a string. The literal hi is declared String, so the second call picks the String version.
Polymorphism
Declared Type and Actual Type
Now the heart of object-oriented design. A variable whose type is a parent may point to an object of any child type, so every variable has two types. The declared type is written in the source, and never changes. The actual type is that of the object made by new, fixed when it's built. The declared type decides what you may call. The actual type decides which version runs. Running different code depending on the object is polymorphism, and picking the version at the moment of the call is dynamic dispatch.
Second Child
Engineer Adds an On-Call Allowance
Here's the second child, Engineer. It overrides pay to add three hundred, and adds a method of its own, review, that managers and plain employees don't have.
Payoff
One Print Method for Every Employee
The payoff is code written once, for the parent, that works for every child, present and future. Payroll's print method knows nothing about managers or engineers. It receives an employee, and asks it to describe itself. Run it, and each object answers in its own way: four thousand, five thousand eight hundred, and six thousand three hundred. If a director type is added next year, Payroll doesn't change at all.
Compile Error
Declared Type Limits the Calls
The declared type's job is easy to see. An engineer object does have a review method, but a variable declared Employee may only use what Employee promises. Cannot find symbol: method review, location, variable e of type Employee. The compiler looked only at the declared type.
Casting
Upcasts, Downcasts and Failed Casts
Moving a reference up the hierarchy, child to parent, is always safe, and needs no syntax. That's an upcast. Moving down is different. An employee reference might hold any kind of employee, so you write the target type in parentheses, a downcast, to say: I take responsibility. When the object really is an engineer, the downcast works, and review is available again: Mei reviews code. But the next cast compiles, and then stops the running program. Class cast exception: class Engineer cannot be cast to class Manager. The object is an engineer, and an engineer is not a manager.
Compile Versus Runtime
Casting Between Sibling Types
Between unrelated types, the compiler refuses outright. Manager and Engineer are siblings, and no object could ever be both, so this cast is incompatible types. Related, but the wrong object: a run-time failure. Unrelated: a compile error. Two different failures, at two different stages.
Safe Casting
Checking With Instanceof First
The operator instanceof asks the question before you risk the cast. It's true when the object is of that type or any child of it, and false for null. Since Java 16, it can also give the checked reference a name in the same step, so g is ready to use inside the if. Run it: true, false, false, and Mei reviews code. If you find yourself checking instanceof for many child types in a row, the design is fighting polymorphism. Put the different behavior in an override instead.
Access Level
Protected Members for Child Types
Inheritance adds a middle access level. A protected member is visible to child types, and to code in the same package, but hidden from everyone else. Intern reads base salary directly, because it's protected. Run it: eleven fifty. Make the field private, and the child is shut out: base salary has private access in Staffer. Protected is a door, not a default. Prefer private fields, with protected or public methods, and open the door only when a child truly needs it.
Root Class
Methods Every Object Inherits
Every type has a parent: write no extends, and Java supplies extends Object. So every object inherits Object's methods, and three matter every day. To string gives the type name, an at sign, and a number. Equals is true only for the very same object. And hash code gives a number from the object's identity. Point overrides nothing. Tagged overrides all three, field by field, and its equals takes an Object, exactly as the parent's does, using instanceof before it reads the other value. Run it. Two points with the same values aren't equal. Tagged prints readably, its two objects are equal, and their hash codes match. Override hash code whenever you override equals: equal objects must give the same number.
Quick Check
A Premium Fee Dispatched at Runtime
Quick check. An account's fee is two. Bill, written in Account, builds a line from fee. Premium overrides fee to triple the parent's. A variable declared Account holds a premium account. What does bill print? Pause, and predict. It prints, fee six point zero. Bill is inherited, but its call to fee is dispatched on the actual object, a premium account, so the override runs: two, times three. The declared type, Account, only decided that bill could be called at all. It compiles, because Account does have a bill method.
Key Takeaways
Extends, Super, Overrides and Casts
To summarize. A child extends one parent, inherits its accessible members, and calls a parent constructor first, with super. Override with at override, and extend the parent's version with super dot method. Overloads are chosen by the compiler, overrides by the running object. The declared type decides what you may call, and the actual type decides which version runs. Guard every downcast with instanceof. And override equals and hash code together, taking an Object.
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